1.

Conductivity of a saturated solution of a sparingly soluble salt AB at 298 K is 1.85 xx 10^(-5) S m^(-1).Solubility product of the salt AB at 298 K is Given ^^_m^(0)(AB) = 140 xx 10^(-4)S m^(2) " mol"^(-1)

Answer»

`5.7 xx 10^(-12)`
`1.32 xx 10^(-12)`
`7.5 xx 10^(-12)`
`1.74 xx 10^(-12)`

SOLUTION :`S_0 = (LAMBDA)/(lambda_0)`
`S = (k)/(1000 lambda_m) = (1.85 xx 10^(-5))/(1000 xx 140 xx 10^(-4))`
`S = 1.3 xx 10^(-6)`
`K_(sp) = S^(2) =(1.3 xx 10^(-6))^(2) = 1.69 xx 10^(-12)`


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