1.

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two types of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or conductivity of the electrolyte solution is given by thefollowing relation: K= cx (l)/(A) where, c=1/R is the conductance and 1/A is the cell constant, Molar conductance (^^_m) andequivalence conductance (^^_e) of an electrolyte solution are calculated using the following similar relations: ^^_m = K xx (1000)/(M) ^^_(e) = K xx (1000)/(N) where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : ^^_m = ^^_m^(0) - b sqrt(C) ^^_m^(0) = molar conductance at infinite dilution C = concentration of the solution b = constant The degrees of dissociation of weak electrolytes are calculated asalpha= (^^_m)/(^^_m^(0)) = (^^_e)/(^^_e^(0)) For which of the following electrolytic solution ^^_m and ^^_e are equal ?

Answer»

`BaCl_2`
`KCl`
`Al_2(SO_4)_3`
`CaCl_2`

SOLUTION :`K^(+) CL^(-) ,^^_(m) = ^^_(e)`


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