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Consider 2 reverse biased diodes. If the ratio of applied reverse bias voltages is 0.5, find the ratio of transition capacitances of the 2 diodes.(a) 2(b) 4(c) 1.31(d) 2.6The question was asked in class test.My question is taken from Transition Capacitance in chapter Diode Circuit of Analog Circuits

Answer»

The correct answer is (c) 1.31

The best EXPLANATION: \(\FRAC{C_{T1}}{C_{T2}} = (\frac{V2}{V1})^{\frac{1}{2.5}} \)

\(\frac{C_{T1}}{C_{T2}}= 2^{\frac{1}{2.5}}\) = 1.31.


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