1.

Consider 3rd orbit of Het (Helium), using non-relativistic approach, the speed of electron in this orbit will be given k = 9 xx 10^(9) constant, Z = 2 and h(Planck's Constant) = 6.6xx10^(-34)JK)

Answer»

`2.92xx10^(6)m//s`
`1.46xx10^(6)m//s`
`0.73xx10^(6)m//s`
`3.0xx10^(6)m//s`

SOLUTION :For ATOM like HYDROGEN
`v=(Z)/(N)xx2.188xx10^(6)`
`:.v=(2)/(3)xx2.188xx10^(6)`
`:.v=1.45866xx10^(6)`
`:.v=1.46xx10^(6)m//s`


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