1.

Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = MV is imparted to the body at one of its ends, what would be its angular velocity?

Answer»

`V//L`
`2V//L`
`V//3L`
`V//4L`

SOLUTION :By LAW of conservation of angular MOMENTUM,
`J=Iomega`
`2M.(L/2)^(2).omega=MV.(L/2). Thereforeomega=V/L`


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