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Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = MV is imparted to the body at one of its ends what would be it angular velocity? A. `V/L`B. `(2V)/L`C. `V/(3L)`D. `V/(4L)` |
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Answer» Correct Answer - A Change an angular momentum of the system` =`angular impulse given to the system `("angular momentum")_f-("angular momenum")_I` `=MVxxL/2` …..i Let the system starts rotating with the angular velocity `omega`. Momentun of inertia of the system about its axis of rotation. (centre of mass of system) `=M(L/2)^(2)+M(L/2)^(2)=(2ML^(2))/4` `=(ML^(2))/2` (from i) `Iomega-0=MVxL/2` `impliesomega=(MV)/IxxL/2=(MV)/((ML^(2))//2)xxL/2=V/L` |
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