1.

Consider a cell given below Cu|Cu^(2+)||Cl^(-)|Cl_(2),Pt, write the reactions that occur at anode and cathode.

Answer»

Solution :* OXIDATION of Cu and reduction of `Cl_(2)`
Oxidation reaction on ANODE:
`Cu_((S)) to Cu_((AQ))^(2+)+2e^(-)`
Reduction reaction on cathode :
`Cl_(2)+2e^(-) to 2Cl_((aq))^(-)`
* Cu of anode dissolve and `Cl_(2)` on cathode liberated as `CL^(-)` due to reduction.


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