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Consider a certain reaction `A rarr` Products with `k=2.0xx10^(-2)s^(-1)`. Calculate the concentration of `A` remaining after `100s` if the initial concentration of `A` is `1.0 mol L^(-1)`. |
Answer» `k = 2.0xx10^(-2) s^(-1)` `T = 100s` ` [A]_(0)=1.0mol^(-1)` Since the unit of k is `s^(−1)`, the given reaction is a first order reaction. `implies 2.0xx10^(-2)s^(-1)=(2.303)/(100s)"log"(1.0)/[A]` `implies 2.0xx10^(-2)s^(-1)=(2.303)/(100s)(-"log"[A])` `implies -log[A]= (2.0xx10^(-2)xx100)/(2.303)` `implies [A]= anti"log"(-(2.0xx10^(-2)xx100)/(2.303))` `0.135"mol"L^(-1)` (approximately) Hence, the remaining concentration of A is` 0.135 "mol"^(-1)` |
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