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Consider a certain reaction A to Products with k=2.0xx10^(-2)s^(-1). Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 mol L"^(-1). |
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Answer» Solution :The units of K indicate that the REACTION is of FIRST order. Hence, `k=(2.303)/(t)"log"([A]_(0))/([A])` Substituting the values, we GET `2.0xx10^(-2)s^(-1)=(2.303)/(100s)"log"(1.0"mol L"^(-1))/([A])` or `log[A]= -0.8684` or ` [A]="Antilog" (-0.8684)="Antilog"(bar1.1316)=0.1354" mol L"^(-1)`. |
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