1.

Consider a chemical reaction 2X + Y rarr X_2Y. The reactant X will decrease at

Answer»

TWICE the RATE at which Y will DECREASE
the same rate at which Y will decrease
twice the rate at which `X_2Y` will form
half the rate at which Y will decrease.

Solution :(a,c) : For a chemical reaction `2X+Y=X_2Y`
Therefore `-(1)/(2)(d[X])/(dt)=-(d[Y])/(dt)=(d[X_2Y])/(dt)`


Discussion

No Comment Found

Related InterviewSolutions