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Consider a coin, It is electrically neutral and contains equal amounts of positive and negative charge of magnitude 34.8 kC. Suppose that these equal charges were concentrated in two point charges separated by (i) 1cm (~(1)/(2)xxdiagonal of the one paisa coin) (ii) 100 m (~length of a long building) (iii) 10^(6)m (radius of the earth). find the force on each such point charge in each of the three cases. what do you conclude from these results? |
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Answer» Solution :Here, `q=+-34.8RC=+-3.48xx10^(4)C` `r_(1)=1cm=10^(-2)m,r_(2)=100m,r_(3)=10^(6)m and (1)/(4piepsi_(0))=9xx10^(9)` `F_(1)=(|q|^(2))/(4piepsi_(0)r_(1)^(2))=(9xx10^(9)(3.48xx10^(4))^(2))/((10^(-2))^(2))=1.09xx10^(23)N` `F_(2)=(|q|^(2))/(4piepsi_(0)r_(2)^(2))=(9xx10^(9)(3.48xx10^(4))^(2))/((100)^(2))=1.09xx10^(15)N` `F_(3)=(|q|^(2))/(4piepsi_(0)r_(3)^(2))=(9xx10^(9)(3.48xx10^(4))^(2))/((10^(6))^(2))=1.09xx10^(7)N` Conclusion from this result we observe that when `+-`charges in ordinary neutral MATTER are separated as POINT charges, they exerted an ENORMOUS force. HENCE, it is very difficult to distrub electrical neutrality of matter. |
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