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Consider a plane `x+y-z=1` and point `A(1, 2, -3)`. A line L has the equation `x=1 + 3r, y =2 -r and z=3+4r`.A. `x-3y+5=0`B. `x+3y-7=0`C. `3x-y-1=0`D. `3x+y-5=0` |
Answer» Correct Answer - b The equation of plane containing the line L is `" "A(x-1)+ B(y-2) + C(z-3)=0`, where `3A-B+4C=0" "` (i) (i) also contains point `A(1, 2, -3)`. Hence, C =0 and `3A= B`. The equation of plane is `x-1+ 3(y-2) =0 or x+ 3y-7=0` |
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