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Consider a point object situated at a distance of 30 cm from the centre of sphere of radius 2 cm and refractive index 1.5 as shown in the figure. If the refractive index of the region surrounding this sphere is 1.4, then the position of the image due to refraction by sphere with respect to the centre is |
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Answer» 30cm For first surface , `n_1 = 1.5 , n_2 = 1.4` `(n_2)/(v)-(n_1)/(v) = (n_2 - n_1)/(R )`u = - 30 cm `R = + 2CM` `(1.4)/(v) - (1.5)/(-30) =(1.5 - 1.4)/(2) RARR (1.4)/(v) = (0.1)/(2) - (1.5)/(30)` `(1.4)/(v) = (3-3)/(30) rArr v= oo` For second surface `(n_2)/(v) - (n_1)/(u) = (n_2 -n_1)/(R)u = oo R = - 2cm ` ` (1.5)/(v) - (1.4)/(oo) = (0.1)/(-2) rArr (1.5)/(v) = 1/20` `v =20 xx 1.5 = 30 cm ` |
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