1.

Consider a point P as the contact point of a wheel on ground which rolls on ground without slipping. Value of displacement of point P when wheel completes half of rotation (Ifradius of wheel is 1 m)

Answer»

2m
`SQRT(pi^(2)+4m)`
`pim`
`sqrt(pi^(2)+2)m`

Solution :
In half ROTATION point P has moved horizontally.
`(pid)/2=pir=pixx1m=pim` `[because` radius=1m`]`
In the same time, it has moved vertically a distance which is EQUAL to its diameter = 2 m.
`THEREFORE` Displacement of P = `sqrt(pi^(2)+2^(2))=sqrt(pi^(2)+4)`m


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