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Consider a thin conducting shell of radius R carrying total charge Q. Two point charges Q and 2Q are placed on points A and B, which are at a distances of R/2 and 2R from the center of the cell respectively as shown in the figure. If the cell is earthed how much charge will flow to the eart? |
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Answer» `3Q` `(KQ^(1))/R+(K(2Q))/(2R)=0` `:. Q^(1)=-Q` Hence `3Q` will flow to the earth
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