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| 1. |
Consider a tightly wound 100 turn coil of radius 10cm, carrying a current of 1A. What is the magnitude of the magnetic field at the centre of the coil? |
| Answer» SOLUTION :`B=(mu_0NI)/(2A)=(4PI xx10^-7 xx100xx1)/(2xx10xx10^-2)=6.28xx10^-4T` | |