1.

Consider a tightly wound 100 turn coil of radius 10 cm, carrying a current of 1 A. What is the magnitude of the magnetic field at the centre of the coil ?

Answer»

Solution :Magnetic FIELD PRODUCED by a current carrying circular coil of radius R with N no. of turns wound tightly at the centre of coil is,
`B=(mu_(0)NI)/(2R)`
`thereforeB=((4pixx10^(-7))(100)(1))/((2)(0.1))`
`thereforeB=6.28xx10^(-4)T`
(Perpendicular to plane of the coil)


Discussion

No Comment Found

Related InterviewSolutions