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Consider a tightly wound 100 turn coil of radius 10 cm,carrying a current of 1 A. What is the magnitude of the magnetic field at the centre of the coil? |
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Answer» Solution : Since the coil is tightly wound, we may take cach circular lement to have the same radius R - 10 cm=0.1 m. The number of tums N=100. The magnitude of the MAGNETIC field is `B = (mu_0 N)/(2R) = (4pi xx 10^(-7) xx 10^(2) xx 1)/(2 xx 10^(-1)) = 2pi xx 10^(-4) = 6.28 xx 10^(-4) T` |
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