1.

Consider a tightly wound 200 turn coil of radius 20 cm, carrying a current of 1A. What is the magnitude of the magnetic field at the centre of the coil ?

Answer»




Solution :If radius of cylindrical conductor is R then MAGNETIC FIELD at distance d from the axis,
`B=(mu_(0)id)/(2piR^(2)),dleRandB=(mu_(0)i)/(2pid),dgtR`


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