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Consider a transparent homogenous hemisphere of refractive index n=2 in front of which a small object is placed in air as shown in figure. |
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Answer» if value of `x=3R` then the final image of the small object OA will be real & inverted. `(2)/(V)-(1)/(-3R)=(2-1)/(R)implies(2)/(V)=(1)/(R)-(1)/(3R)` `(2)/(V)=(2)/(3R)impliesV=3R` for second surface `u=2R` `(1)/(V)=(2)/(2R)impliesV=R` Real & inverted. (B) for first surface `(2)/(V)-(1)/(-2R)=(2-1)/(R)implies(2)/(V)=(1)/(R)-(1)/(2R)` `impliesV=4Rimpliesm_(1)=-1` for second surface `u=3R` `(1)/(V)=(2)/(3R)impliesV=(3R)/(2)` real & inverted and same SIZE.
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