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Consider a uniform rod of mass m and length 2l with two particles of mass `m` each at its ends. Let AB be a line perpendicular to the length of rod and passig through its centre. Find the moment of inertial of the system about AB. |
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Answer» Moment of inertia of the system about AB `I_(AB)=I_("rod")+I_("both particles")` `=(m(2l)^(2))/(12)+2(ml^(2))=(7)/(3)ml^(2)`. |
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