1.

Consider a uniform square plate of side 'a' and mass 'm'. The moment of inertia of the plate about an axis perpendicular to its plane and passing through one of its corners is :

Answer»

`(5)/(6)ma^(2)`
`(1)/(12)ma^(2)`
`(7)/(12)ma^(2)`
`(2)/(3)ma^(2)`

Solution :`I_(N n.)=(1)/(12)M(a^(2)+a^(2))=(Ma^(2))/(6)`
Also `DO=(DB)/(2)=SQRT(2a)/(2)=(a)/(sqrt(2))`
According to parallel axis theorem
`I_(mm.)=I_(n n.)+M((a)/(sqrt(2)))^(2)`
`=(Ma^(2))/(2)+(Ma^(2))/(2)`
`=(Ma^(2)+3MA^(2))/(6)=(2)/(3)Ma^(2)`


Discussion

No Comment Found

Related InterviewSolutions