Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, he average time of collision between molecules increases as V^(q), where V is the volume of gas. The value of q is: (gamma =(C_(p))/(C_(v)))

Consider an ideal gas confined in an isolated closed chamber. As the g

1.	Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, he average time of collision between molecules increases as V^(q), where V is the volume of gas. The value of q is: (gamma =(C_(p))/(C_(v)))
Answer» `(3 gamma -5)/(6)` `(gamma +1)/(2)` `(gamma-1)/(2)` `(3 gamma +5)/(6)` Solution :`tau =(l)/(v_(rms)) =(1)/(sqrt(2)pi d^(2)((N)/(V))sqrt((3RT)/(M)))" …(i)"` `tau prop (V)/(sqrt(T))" ….(ii)"` `TV^(gamma-1)=K"….(iii)"` `THEREFORE tau prop V^((gamma+1)/(2))` So CORRECT CHOICE is (b).

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Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, he average time of collision between molecules increases as V^(q), where V is the volume of gas. The value of q is: (gamma =(C_(p))/(C_(v)))

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