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Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average time of collision between molecules increase as `V^q`, where V is the volume of the gas. The value of q is : `(gamma=(C_p)/(C_v))`A. `(3gamma+5)/(6)`B. `(3gamma-5)/(6)`C. `(gamma+1)/(2)`D. `(gamma-1)/(2)` |
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Answer» Correct Answer - C `tau=(gamma)/(V_("max"))=(1)/(sqrt(2)pid^(2)((N)/(V))sqrt((3RT)/(M)))` `tauprop(V)/sqrt(T)` `TV^(gamma-1)=k` `taupropV^((gamma+1)/(2))` |
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