1.

Consider four independent trials in which an event A occurs with probability 1/3 in any single trial. The event B occurs with probability 1 if the event A occursat least twice,it cannotoccur if the event A does not occur and it occurs with probability 1/2 if the event A occurs onlyonce. If the probability p of the occurrence of event 'B' can be expressed as m/n ,then the least value of (m + n), where m, n in N, is

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Solution :P(B)=1 if the event 'A' occurs ATLEAST twice
P(B)=0 if the event'A' does not occur
`P(B)=1/2` If 'A' occurs once
`P(B)=.^4C_1(1/3)(2/3)^2(1/2)+(.^4C_2(1/3)^2(2/3)^2 + .^4C_3(1/3)^3 (2/3)^1 + .^4C_4(1/3)^4)(1)`
`=49/81`


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