1.

Consider Fraunhoffer diffraction pattern obtained with a single slit at normal incidence.At the angular paosition of first diffraction minimum, the phase difference between the wavelets from the opposite edges of the slit is

Answer»

`(PI)/(4)`
`(pi)/(2)`
`pi`
`2PI`

Solution :To have the FIRST minimum, the PATH difference between the waves from A and B = BD = `a/2, sin theta = (lambda)/(2)`.The path difference between the waves from A and C at the same point should be `lambda` or phasedifference is `2pi`


Discussion

No Comment Found

Related InterviewSolutions