1.

Consider fraunhoffer diffraction pattern obtained with a single slit illuminated at normal indicent. At the angular position of the first diffraction minimum the phase different between the wavelets from the opposite edge of the slits is

Answer»

`(PI)/(4)`
`(pi)/(2)`
`2PI`
`pi`

Solution :At the angular position of first minimum waveles from opposite EDGES of the SLITS have a path difference of `LAMBDA` and a phase difference of `2pi` radian.


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