Consider its input resistance to be R1. Now, the bypass capacitor is attached, so that the new input resistance is R2. Given that hie = 1000Ω and hfe = 50, find R1-R2.(a) 112.2Ω(b) 0Ω(c) 110Ω(d) 200ΩI have been asked this question in an international level competition.Enquiry is from Hybrid Equivalent Model in chapter Transistor Biasing and Low Frequencies of Analog Circuits

Consider its input resistance to be R1. Now, the bypass capacitor is a

1.	Consider its input resistance to be R1. Now, the bypass capacitor is attached, so that the new input resistance is R2. Given that hie = 1000Ω and hfe = 50, find R1-R2.(a) 112.2Ω(b) 0Ω(c) 110Ω(d) 200ΩI have been asked this question in an international level competition.Enquiry is from Hybrid Equivalent Model in chapter Transistor Biasing and Low Frequencies of Analog Circuits
Answer» Right option is (a) 112.2Ω Easiest explanation: For the circuit, CE amplifier without bypass capacitor, INPUT RESISTANCE, R1=hie + (1+hfe)RE R1 = 1000 + 51*2.2 = 1000 + 112.2 = 1112.2Ω With a bypass capacitor attached, input resistance, R2 = hie = 1000Ω Thus R1 – R2 = 112.2Ω.

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