Consider one of fission reactions of ^(235)U by thermal neutrons ._(92)^(235)U +n rarr ._(38)^(94)Sr +._(54)^(140)Xe+2n . The fission fragments are however unstable and they undergo successive beta-decay until ._(38)^(94)Sr becomes ._(40)^(94)Zr and ._(54)^(140)Xe becomes ._(58)^(140)Ce. The energy released in this process is Given: m(.^(235)U) =235.439u,m(n)=1.00866 u, m(.^(94)Zr)=93.9064 u, m(.^(140)Ce) =139.9055 u,1u=931 MeV] .

Consider one of fission reactions of ^(235)U by thermal neutrons ._(92

1.	Consider one of fission reactions of ^(235)U by thermal neutrons ._(92)^(235)U +n rarr ._(38)^(94)Sr +._(54)^(140)Xe+2n . The fission fragments are however unstable and they undergo successive beta-decay until ._(38)^(94)Sr becomes ._(40)^(94)Zr and ._(54)^(140)Xe becomes ._(58)^(140)Ce. The energy released in this process is Given: m(.^(235)U) =235.439u,m(n)=1.00866 u, m(.^(94)Zr)=93.9064 u, m(.^(140)Ce) =139.9055 u,1u=931 MeV] .
Answer» `156 MEV` `208 MeV` `465 MeV` cannot be computed Solution :The complete fission is `._(92)^(235)U + n rarr ._(40)^(94)Zr +._(58)^(140)Ce + 2n+6e^(-1)` `Q =[m(.^(235)U) - m(.^(94)Zr) - m(.^(140)Ce) -m(n)]c^(2)` `=208 MeV`.

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