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Consider sunlight incident on a slit of width 10^(4)Å. The image seen through the slit shall |
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Answer» be a fine sharp slit white in colour at the center. Here average wavelength in the visible light is `lamda=(4000+8000)/(2)=6000Å` and here, width of slit is `d=10^(4)Å=10000Å` `(lamda)/(d)=(6000)/(10000)=0.6implies(lamda)/(d)lt1` Amount of diffraction will be quite small. Hence image of slit will be quite sharp in which central region will appear white because of superposition of constituent colours in equal proportion. Moreover, due to zero PHASE difference, the superposing waves will interfere constructively GIVING rise to central maximum with maximum intensity. |
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