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Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stopcocks are opened. Assuming that temperature remain constant. (Neglect the volume of capollary tubing connecting bulbs) |
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Answer» 440 torr For `O_(2)` gas `P_(1) V_(1) = P_(2) V_(2)` `P_(1) = 300` torr, `P_(2)` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `300 XX 1 = P_(2) xx 2.5` `P_(2) = 120` torr For He gas `P_(1) V_(1) = P_(2)V_(2)` `P_(1) = 600` torr, `P_(2) =` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `600 xx 1 = P_(2) xx 2.5` `P_(2) = 240` torr For `N_(2)` gas `P_(1)V_(1) = P_(2)V_(2)` `P_(1) = 400` torr, `P_(2) =` ? `V_(1) = 0.5` litre, `V_(2) = 2.5` litre `400 xx (1)/(2) = P_(2) xx (5)/(2)` `P_(2) = 80` torr Pressure of SYSTEM `= P_(O_(2)) + P_(N_(2)) + P_(He)` `= 120 + 80 + 240` `= 440` torr |
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