1.

Consider the cell reaction Zn+Cu^(2+)(aq)iff Cu + Zn^(2+) (aq). Reaction quotient is Q = ([Zn^(2+)])/([Cu^(2+)])E^(0) of the cell is 1.10V. Now, E_(cell) will be 1.159V when:

Answer»

`([Cu^(2+)])/([ZN^(2+)]) = 0.01`
`([Zn^(2+)])/([Cu^(2+)]) = 0.01`
`([Zn^(2+)])/([Cu^(2+)]) = 0.1`
`([Zn^(2+)])/([Cu^(2+)]) = 1`

ANSWER :B


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