Consider the chemical reaction `N_(2) (g) + 3H_(2)(g) to 2NH_(3) (g)`. The rate of this reaction can be expressed in terms of time derivated of concentration of `N_(2)(g) , H_(2) (g)` or `NH_(3) (g)` . Identify the correct relationship amongst the rate expressions .A. Rate = -d[`N_(2)`]/dt = `-1//3` d [ `H_(2)`] / dt = 1/2 [`NH_(3)`] /dtB. Rate = `-d[N_(2)`]/dt = `-3d[H_(2)]`/dt = 3d `[NH_(3)`]/dtC. Rate = d`[N_(2)`] /dt = 1/3d[`H_(2)`]/dt = 1/2 d `[NH_(3)]`/dtD. Rate = `-d[N_(2)]`/dt = `-d[H_(2)]`/dt = d`[NH_(3)]`/dt

Consider the chemical reaction `N_(2) (g) + 3H_(2)(g) to 2NH_(3) (g)`.

1.	Consider the chemical reaction `N_(2) (g) + 3H_(2)(g) to 2NH_(3) (g)`. The rate of this reaction can be expressed in terms of time derivated of concentration of `N_(2)(g) , H_(2) (g)` or `NH_(3) (g)` . Identify the correct relationship amongst the rate expressions .A. Rate = -d[`N_(2)`]/dt = `-1//3` d [ `H_(2)`] / dt = 1/2 [`NH_(3)`] /dtB. Rate = `-d[N_(2)`]/dt = `-3d[H_(2)]`/dt = 3d `[NH_(3)`]/dtC. Rate = d`[N_(2)`] /dt = 1/3d[`H_(2)`]/dt = 1/2 d `[NH_(3)]`/dtD. Rate = `-d[N_(2)]`/dt = `-d[H_(2)]`/dt = d`[NH_(3)]`/dt
Answer» Correct Answer - c Individual rates become equal when eachof these are divided by their respective stoichiometric coefficient . Further the rate of the consumption of the reactant goes on decreasing and the rate of formation of the product goes on increasing with time hence -ve and +ve sign , respectively .

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