1.

Consider the circuit consisting of two capacitors having capacitances 3 mu F and 6 mu F and an ideal battery of emf e = 4 volts as shown. The switch S is open for a long time and then closed. After the switch is closed. The work done by the battery is :

Answer»

16 m J
32 m J
64 m J
128 m J

Solution :Initial charge on 6 mF CAPACITOR
`= (3 XX 6)/(3+6) xx 4 = 8 mC`
final charge on 6mF capacitor `= 6 xx 6 = 25 mC` charge PASSING through cell (in direction aided by cell) `= q_(f) -q_(i) = Dq = 24 - 8 = 16 mC` work done by cell = Dqe `= 16 xx 4 = 64 mJ`


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