1.

Consider the circuit shown in figure . With switch S_(1) closed and the other two switches open, the circuit has a time constant 0.05 sec. With switch S_(2) closed and the other two switches open, the circuit has a time constant 2 sec. With switch S_(3) closed and the other two switches open, the circuit oscillates with a period T. Find T ( in sec ) . ( Take pi ^(2)=10)

Answer»


SOLUTION :`tau_(1)=RC,tau_(2)=(L)/(R)impliesLC=tau_(1)tau_(2)=0.1sec`
`impliesT=2pi sqrt(LC)=2pisqrt((1)/(10))=2sec`


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