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Consider the circuit shown where C_(1) = 6 mu F, C_(2) = 3 mu F and V=20 V. Capacitor C_(1) is first charged by closing the switch S_(1). Switch S_(1) is then opened, and the charged capacitor is connected to the uncharged capacitor C_(2) by closing S_(2). |
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Answer» Total charge that has FLOWN through the battery is `120 MU C.` |
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