1.

Consider the collision depicted in Figure, to be between two billiard balls with equal masses `m_(1)=m_(2)`. The first ball is called the cue and the second ball is called the target. The billiard player wants to sink the target ball in a corner pocket, which is at an angle `theta_(2)=phi=37^(@)`. Assume that the collision is elastic and that friction and rotational motion are not important. Obtain `theta_(1)=theta` .A. `37^@`B. `90^@`C. `45^@`D. `53^@`

Answer» Correct Answer - D
`theta_(1) + theta_(2) = 90^@`.


Discussion

No Comment Found

Related InterviewSolutions