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Consider the conductor to be a coil of turns 60 and the flux density to be 13.5 units, current 0.12A and area 16units. The torque will be(a) 1555.2(b) 1222.5(c) 525.1(d) 255.6I got this question in homework.Question is taken from Magnetic Torque topic in division Magnetic Forces and Materials of Electromagnetic Theory

Answer»

The correct option is (a) 1555.2

Explanation: For a single turn or LOOP, the torque will be BIA. For N turns, the torque will be T = NBIA, where N = 60, B = 13.5, I = 0.12 and A = 16. THUS T = 60 X 13.5 x 0.12 x 16 = 1555.2 UNITS.



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