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Consider the D - T reaction (deuterium - tritium fusion) ._(1)^(2)H+ ._(1)^(3)H to ._(2)^(4)He + n Calculate the energy released in MeV in this reaction from the data : m(._(1)^(2)H)=2.014102 u m(._(1)^(3)H)=3.016049 u |
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Answer» SOLUTION :`A=[m(""_(1)^(2)H)+m(""_(1)^(3)H)-m(""_(2)^(4)He)-m(n)]c^(2)=17.59MeV` (b) K.E. REQUIRED to overcome COULOMB repulsion = 480.0 keV `480.0 KeV=7.68xx10^(-14)J=3kT` therefore `T=(7.68xx10^(-14))/(3xx1.381xx10^(-23))""("as "k=1.381xx10^(-23)JK^(-1))` `=1.85xx10^(9)K"(required temperature)"` |
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