1.

Consider the diffraction pattern for a small pinhole. As the size of the hole is increased

Answer»

the size DECREASES.
the INTENSITY increases.
the size increases.
the intensity decreases.

Solution :We know that amount of DIFFRACTION is determined from ratio `((lamda)/(d))`. Here by increasing d, amount of diffraction decreases and so width of diffraction PATTERN decreases. Thus option (A) is correct.
Here power of radiation made incident on the slit is constant. Hence, after passing through slit, if such light is made incident on smaller region then naturally, intensity obtained in that region would be more because `I=(P)/(A)implies` when P = constant, `Iprop(P)/(A)implies` If A decreases then I A must increase `implies`Option (B) is correct.


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