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| 1. |
Consider the earth as a short magnet with its centre coinciding with the centre of earth . Show that the angle of dip phi is related to magnetic latitudelambdathrough the relationtan phi = 2 tan lambda |
Answer» Solution : consider the SITUATION as shown in the figure . For DIPOLE , at position ` (r , theta )` we have `B_r = (mu_0)/(4pi)(2 M COS theta )/(r^(3)) and B_0 = (mu_0)/( 4pi)(Msin theta )/(r^(3))` .......... (1) and as ` tan phi = (B_V)/(B_H) = -(B_r)/(B_(theta))`, so in the LIGHT of eq (1) , ` tan phi =-2 cot theta ` But from figure ` theta = 90 + lambda ` so , ` tan phi = -2 cot (90 + lambda )` , i.e., ` than phi = 2 tan lambda`. |
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