Consider the equation (1+ a + b)2 = 3(1+ a2 + b2 ), where a , b are re

1.	Consider the equation (1+ a + b)2 = 3(1+ a2 + b2 ), where a , b are real numbers. Then (A) there is no solution pair (a, b) (B) there are infinitely many solution pairs (a, b) (C) there are exactly two solution pairs (a, b) (D) there is exactly one solution pair (a, b)
Answer» Correct Option :- (D) there is exactly one solution pair (a , b) Explanation :- (1 + a + b)² = 3 (1 + a² + b² ) ⇒ 1 • a + a • b + 1 • b = 1² + a² + b² ⇒ 1 = a = b exactly one pair.

Consider the equation (1+ a + b)2 = 3(1+ a2 + b2 ), where a , b are real numbers. Then (A) there is no solution pair (a, b) (B) there are infinitely many solution pairs (a, b) (C) there are exactly two solution pairs (a, b) (D) there is exactly one solution pair (a, b)

Answer»

Correct Option :- (D) there is exactly one solution pair (a , b)

Explanation :-

(1 + a + b)² = 3 (1 + a² + b² )

⇒ 1 • a + a • b + 1 • b = 1² + a² + b²

⇒ 1 = a = b

exactly one pair.

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Consider the equation (1+ a + b)2 = 3(1+ a2 + b2 ), where a , b are real numbers. Then (A) there is no solution pair (a, b) (B) there are infinitely many solution pairs (a, b) (C) there are exactly two solution pairs (a, b) (D) there is exactly one solution pair (a, b)

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