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Consider the expansion `(x^(2)+(1)/(x))^(15)`. What is the sum of the coefficients of the middle terms in the given expansion ?A. C(15, 9)B. C(16, 9)C. C(16, 8)D. None of these |
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Answer» Correct Answer - C Given `(x^(2)+(1)/(x))^(15)` Since, n is odd. So, it has two middle terms `T_(8) and T_(9)`. `therefore T_(8)+T_(9)=.^(15)C_(7)+.^(15)C_(8)=.^(16)C_(8)" "(because .^(n)C_(r-1)+.^(n)C_(r)=.^(n+1)C_(r))` |
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