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Consider the figure and answer the following questions. (i) Cell 'A' has E_(cell)2V and cell 'B' has E_(cell)=1.1V which of the two cells 'A' or 'B' will act as an electrolytic cell. Which electrode reactions will occur in this cell ? (ii) If cell 'A' has E_(cell)=0.5Vand cell 'B' has E_(cell)=1.1V then what will be the reaction at anode and cathode ? |
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Answer» Solution :(i) Cell .B. will act as electrolytic cell as it has lower EMF `therefore` The electrode reactions will be: Reduction at cathode : `Zn^(2+)+2E^(-) to Zn` Oxidation at anode : `CU to Cu^(2+) +2e^(-)` (ii) Now cell .B. ACTS as galvanic cell as it has higher emf and will push ELECTRONS into cell .A.. The electrode reaction will be : At anode : `Zn to Zn^(2+) + 2e^(-)` At cahotde : `CutoCu^(2+)+2e^(-)` |
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