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Consider the figure and answer the questions (i) to (vi) gives below. (i) Redraw the diagram to show the direction of electron flow. (ii) Is silver plate the anode or cathode ? (iii) What will happen if salt bridge is removed ? (iv) When will the cell stop functioning ? (v) How will concentration of Zn^(2+) ions and Ag^(+) ion be affected when the cell functions ? (vi) How will the concentration of Zn^(2+) ions and Ag^(+) ions be affected after the cell becomes 'dead' ? |
Answer» Solution :(i) Electrons move from ZN to Ag. (II) It acts as cathode. (ii) Cell will stop functioning. (iv) When equilibrium is attained i.E., `E_(cell)=0`. (v) CONCENTRATION of `Zn^(2+)` will increase and `Ag^(+)` ions will decrease. (vi) When `E_(cell)=0` (equilibrium is REACHED), concentration of `Zn^(2+)` ions and `Ag^(+)` ions will not change. |
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