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Consider the figure below and answer the following questions : (i) Cell 'A' has E_(cell)=2" V " and Cell B has E_(cell) =1.1" V " which of the two cells 'A' or 'B' will act as an electrolytic cell. Which electrode reactions will occur in this cell ? (ii) If cell 'A' has E_(cell)=0.5" V " and cell 'B' has E_(cell) =1.1" V " then what will be the reactions at anode and cathode ? |
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Answer» Solution :(i) SINCE the cell (B) has low e.m.f. , it will act as electrolytic cell. In the cell, the ELECTRODE reaction that takes PLACE is : `Zn^(2+)(AQ)+2e^(-) to Zn(s)""("At cathode")` `Cuoverset((aq)) rarr Cu^(2+)(aq)+2e^(-)` (ii) The data shows that the cell 'B' will act as electrochemical cell since its `E_(cell)`. (1.1V) is mre than that of cell 'A' (0.5V).The electrode reactions which TAKE place are : `Zn(s) to Zn^(2+)(aq)+2e^(-)"" ("At anode")` `Cu^(2+)(aq)+2e^(-) to Cu(s)"" ("At cathode")` |
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