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Consider the figure below and answer the following questions : (i) Cell 'A' has E_("cell") = 2V and Cell 'B' has E_("cell") = 1.1 V which of the two cells 'A' or 'B' will act as an electrolytic cell. Which electrode reaction will occur in this cell? (ii) If cell 'A' has E_("cell") = 0.5 V and cell 'B' has E_("cell") =1.1 V then what will be the reaction at anode and cathode? |
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Answer» Solution :(i) Cell .B. will act as electrolytic cell as it has lower emf. The electrode reactions will be : `ZN^(2+) + 2e^(-) to Zn` at cathode `Cu to Cu^(2+) + 2e^(-)` at ANODE. (ii) Now cell .B. acts as GALVANIC cell as it has higher emf and will push electrons into cell .A.. The electrode reaction will be : `{:("At anode", Zn to Zn^(2+) + 2e^(-)),("At cathode", Cu^(2+) + 2e^(-) to Cu):}` |
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