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Consider the first 10 positve integers .If we multiply each number by -1 and then add 1 to each number,the variance of the number so obtainedA. 8.25B. 6.5C. 3.87D. 2.87 |
Answer» Correct Answer - A Since the first 10 positive intergers are 1,2,3,4,5,6,7,8, 9, and 10 on multiplying by-1 we get -1,-2,-3,-4,-5,-6,-7,-8,-9,-10 On adding 1 in each number ,we get 0 -1,-2,-3,-4,-5,-6,-7,-8,-9 `therefore " " Sigmax_(i)=0-1-2-3-4-5-6-7-8-9` `=-(9xx10)/2` = - 45 `Sigma x_(i)^(2)=0^(2)+(-1)^(2)+(-2)^(2)+...+(-9)^(2)` `- (9xx10xx190)/(6)` 285 `therefore " " SD =sqrt((285)/10-((-45)/10)^(2))=sqrt(285/10-2025/100)` `=sqrt((2850-2025)/100)=sqrt(8.25)` Now variance `=(SD)^(2)=(sqrt(8.25)^(2)=8.25` |
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