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Consider the fission of " "_(92)^(238)U by fast neutrons. In one fission event, no neutrons are emitted and the final end products, after the beta decay of the primary fragments, are " "_(58)^(140)Ce and " "_(44)^(99)Ru. Calculate Q for this fission process. The relevant atomic and particle masses are m(" "_(92)^(238)U) = 238.05079 u, m(" "_(58)^(140)Ce) = 139.90543 u, m(" "_(44)^(99)Ru) = 98.90594 u. |
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Answer» Solution :For the FISSION `" "_(92)^(238)U +N to " "_(58)^(140)Ce + " "_(44)^(99)Ru +Q` `Q = [m (" "_(92)^(238)U) + m_(n) -m (" "_(58)^(140)Ce) - m(" "_(44)^(99)Ru)]c^(2)= [238.05079 + 1.00867 - 139.90543 - 98.90594] u xx c^(2) = 0.24809 u xx 931.5 MeV = 231.1 MeV`. |
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