1.

Consider the following Born-Haber's cycle: (Where DeltaH_(1),DeltaH_(2),DeltaH_(3),DeltaH_(4),DeltaH_(5) and DeltaH_(6) are in kJ/mol) Then according to given information the correct statement is/are:

Answer»

`DeltaH_(2) and DeltaH_(3)` are always POSITIVE
`DeltaH_(1)=2DeltaH_(2)+(3)/(2)DeltaH_(3)+2DeltaH_(4)+3DeltaH_(5)+DeltaH_(6)`
Second ELECTRON gain enthalpy of X is NEGATIVE
`DeltaH_(1)` must be negative for formationn of `B_(2)X_(5)`(s)

Solution :`impliesDeltaH_(1)=2DeltaH_(2)+(3)/(2) DeltaH_(3)+2DeltaH_(4)-3DeltaH_(5) implies`second electron gain enthalpy of X will be positive.


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